util.C

#include <iostream.h>
#include <math.h>
#include "qureg.C"
#define PI 3.14159265359

//This function takes an integer input and returns 1 if it is a prime
//number, and 0 otherwise.
int TestPrime(int n) {
  int i;
  for (i = 2 ; i <= floor(sqrt(n)) ; i++) {
    if (n % i == 0) {
      return(0);
    }
  }
  return(1);
}

//This function takes an integer input and returns 1 if it is equal to a 
//prime number raised to an integer power, and 0 otherwise.
int TestPrimePower(int n) {
  int i,j;
  j = 0;
  i = 2;
  while ((i <= floor(pow(n, .5))) && (j == 0)) {
    if((n % i) == 0) {
      j = i;
    }
    i++;
  }
  for (int i = 2 ; i <= (floor(log(n) / log(j)) + 1) ; i++) { 
    if(pow(j , i) == n) {
      return(1);
    }
  }
  return(0);
}

//This function computes the greatest common denominator of two integers.
//Since the modulus of a number mod 0 is not defined, we return a -1 as
//an error code if we ever would try to take the modulus of something and
//zero.
int GCD(int a, int b) {
  int d;
  if (b != 0) {
    while (a % b != 0) {
      d = a % b;
      a = b;  
      b = d;
    }
  } else {
    return -1;
  }
  return(b);
}

//This function takes and integer argument, and returns the size in bits
//needed to represent that integer.
int RegSize(int a) {
  int size = 0;
  while(a != 0) {
    a = a>>1;
    size++;
  }
  return(size);
}


//q is the power of two such that n^2 <= q < 2n^2.
int GetQ(int n) {
  int power = 8; //265 is the smallest q ever is.
  while (pow(2,power) < pow(n,2)) {
    power = power + 1;
  }
  return((int)pow(2,power));
}

//This function takes three integers, x, a, and n, and returns x^a mod n.
//This algorithm is known as the "Russian peasant method," I belive.
int modexp(int x, int a, int n) {
  int value = 1;
  int tmp;
  tmp = x % n;
  while (a > 0) {
    if (a & 1) {
      value = (value * tmp) % n;
    }
    tmp = tmp * tmp % n;
    a = a>>1;
  }
  return value;
}


// This function finds the denominator q of the best rational
// denominator q for approximating p / q for c with q < qmax.
int denominator(double c, int qmax) {
  double y = c;
  double z;
  int q0 = 0;
  int q1 = 1;
  int q2 = 0;
  while (1) {
    z = y - floor(y);
    if (z < 0.5 / pow(qmax,2)) { 
      return(q1); 
    }
    if (z != 0) {
      //Can't divide by 0.
      y = 1 / z;
    } else {
      //Warning this is broken if q1 == 0, but that should never happen.
      return(q1);
    }
    q2 = (int)floor(y) * q1 + q0;
    if (q2 >= qmax) { 
      return(q1); 
    }
    q0 = q1; 
    q1 = q2;
  }
}

//This function takes two integer arguments and returns the greater of
//the two.
int max(int a, int b) {
  if (a > b) {
    return(a);
  }
  return(b);
}

//This function computes the discrete Fourier transformation on a register's
//0 -> q - 1 entries. 
void DFT(QuReg * reg, int q) {
  //The Fourier transform maps functions in the time domain to
  //functions in the frequency domain.  Frequency is 1/period, thus
  //this Fourier transform will take our periodic register, and peak it
  //at multiples of the inverse period.  Our Fourier transformation on
  //the state a takes it to the state: q^(-.5) * Sum[c = 0 -> c = q - 1,
  //c * e^(2*Pi*i*a*c / q)].  Remember, e^ix = cos x + i*sin x.

  Complex * init = new Complex[q];
  Complex tmpcomp;
  tmpcomp.Set(0,0);

  //Here we do things that a real quantum computer couldn't do, such
  //as look as individual values without collapsing state.  The good
  //news is that in a real quantum computer you could build a gate
  //which would what this out all in one step.

  int count = 0;
  double tmpreal = 0;
  double tmpimag = 0;
  double tmpprob = 0;
  for (int a = 0 ; a < q ; a++) {
    //This if statement helps prevent previos round off errors from
    //propogating further.
    if ((pow(reg->GetProb(a).Real(),2) + 
	 pow(reg->GetProb(a).Imaginary(),2)) > pow(10,-14)) {
      for (int c = 0 ; c < q ; c++) {
	tmpcomp.Set(pow(q,-.5) * cos(2*PI*a*c/q),
		    pow(q,-.5) * sin(2*PI*a*c/q));
	init[c] = init[c] + (reg->GetProb(a) * tmpcomp);
      }
    }
    count++;
    if (count == 100) {
      cout << "Making progress in Fourier transform, " 
	   << 100*((double)a / (double)(q - 1)) << "% done!" 
	   << endl << flush;
      count = 0;
    }
  }
  reg->SetState(init);
  reg->Norm();
  delete [] init;
}